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Algebra


LRW November 13, 2008 05:56 AM

Algebra
 
:banghead: I'm stuck on one problem, I just can't find any factors in it.

112a^2-168a+63

Numbers I've tried:
3
4
6
7
8
9
14
13
15
16
17
18
19
21

sosia November 13, 2008 06:23 AM

I suppose it's 112a^2-168a+63 = 0
ECUACIÓN DE SEGUNDO GRADO ax2+bx+c=0
Quadratic ecuation (wikipedia or here)
Las soluciones de la ecuación vienen dadas por x=(-b± sqr(b2-4ac))/(2a)
112a^2-168a+63 = 0
--->
a = (+168 ± sqrt(168*168-4*112*63))/(2*112)
a = (+168 ± sqrt(28224-28224))/(224)
a = (+168 ± sqrt(0))/(224)
a = (+168 ± 0))/(224)
a = (+168)/(224)
a= 0,75 aka 3/4

saludos

LRW November 13, 2008 06:28 AM

I completely forgot about the quadratic formula, that would have saved me a major headache...

Thank you!

sosia November 13, 2008 06:33 AM

de nada :D

Tomisimo November 13, 2008 11:10 AM

Moved to the General Chat forum, since the Practice and Homework forum is for Spanish or English language related practice or homework help.


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