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Rant about Spanish documentaries


Perikles April 06, 2011 06:53 AM

Rant about Spanish documentaries
 
They are all the same. Take this one (The one on the right about magic squares). Here is a mathematician explaining a simple maths problem. I had solved it myself, but wanted to hear what he had to say. And I can't. Why? Because every time somebody has something to say they superimpose background music so loud that you can't hear what the person is saying. Why do they do that? Why make things deliberately more difficult than necessary?

Is it just me? :thinking:

aleCcowaN April 06, 2011 08:27 AM

Suben el volumen de la música para cubrir que el tío, la primera vez masculla, y la más prolongada al final, no está diciendo nada.

irmamar April 06, 2011 12:27 PM

Quote:

Originally Posted by Perikles (Post 108626)
They are all the same. Take this one (The one on the right about magic squares). Here is a mathematician explaining a simple maths problem. I had solved it myself, but wanted to hear what he had to say. And I can't. Why? Because every time somebody has something to say they superimpose background music so loud that you can't hear what the person is saying. Why do they do that? Why make things deliberately more difficult than necessary?

Is it just me? :thinking:

Yes, I agree, I thought the same when he set out the problem the other day :mad:. For this time, and without being a precedent :rolleyes: :D, I'll copy the first part of the solution:


En lugar de escribir directamente el cuadrado mágico,
vamos a explicar dos estrategias diferentes que permiten encontrar ese cuadrado.

Cuando nos encontramos un problema de matemáticas, de
hecho cualquier problema, lo primero es intentar lo más sencillo.
Lo más sencillo en este problema es suponer que quizás uno de los
otros números es el 1. Vamos a ponerle aquí un 1. Si eso es así, si
eso fuera así, entonces, como el producto de estos tres
números de la segunda fila tiene que ser igual al producto
de los tres números de la tercera columna, necesariamente
el producto de los dos números de las esquinas tiene que ser
15, y eso solo es posible con el 3 y el 5, porque el 1 y el 15 no los
podemos poner porque estaríamos repitiendo los números.
Vamos a poner aquí el 3 y el 5.

Ahora ya es muy sencillo porque si nos fijamos en esta diagonal
y en esta fila, ocurre que el producto de estos dos números,
3 x 15 = 45, tiene que ser igual 5 por el número que pongamos
aquí (tiene que ser el 9). Argumentando de la misma manera,
el producto de estos dos números, que es 75, tiene que ser igual
al producto de 3 por el que pongamos aquí, tiene que ser 25.

Y ahora ya es muy fácil porque ya hemos completado
una columna, ya sabemos el producto. Ya completamos
directamente el cuadrado.

Por supuesto, cualquier giro de este cuadrado, cualquier
simetría por ejemplo, cambiar la 3ª columna por la 1ª también
nos da la solución del problema. Hay 8 cuadrados posibles, pero
todos ellos utilizando los mismos números(?).


Surely, you wanted the second part. :thinking: :D

Perikles April 06, 2011 01:36 PM

Quote:

Originally Posted by irmamar (Post 108647)
Surely, you wanted the second part. :thinking: :D

That was very kind of you, but I had guessed what he had to say by following what he was writing. I understood the second part as well. It is just a pity that I can't hear him. I need to send them an e-mail with my complaint (not that I didn't win the prize, even when I had the correct answer, but that I can't hear him :rolleyes:). I actually thought his method was rather poor, and mine was far superior. :D

irmamar April 07, 2011 12:28 AM

Bueno..., demuéstralo entonces... :D

CrOtALiTo April 07, 2011 11:39 AM

Huuu

That answer sounded very aggressor hahahaha.

I don't what are you talking about, but I believe are you in the correct.

Greetings.

irmamar April 08, 2011 02:37 AM

I didn't want to show myself aggressive at all :eek: . This was a challenge that Perikles has not understood, as I can see. :D :kiss:

CrOtALiTo April 08, 2011 10:17 AM

Hahahaha.

Don't worry.
That was just a joke!

Bye bye


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