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Math question - TriangleTalk about anything here, just keep it clean. |
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#2
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your answer is correct.
However, the way to solve it is to use a system of equations and solve for the variables. A = measure of angle A B = measure of angle B C = measure of angle C A = B + 30 C = B + 60 A + B + C = 180 Now substitute into the A + B + C equation so that there is only 1 variable which u can then solve for. A + B + C = 180 <<sub (B +30) in for A, & (B+60) in for C>> (B + 30) + B + (B + 60) = 180 << combine like terms>> 3B + 90 = 180 <<subtract 90 from each side>> 3B = 90 <<divide each side by 3>> B = 30 Now you know B = 30 degrees. To solve for A and C just input 30 for B back in the original equations. A = B + 30 A = 30 + 30 A = 60 C = B + 60 C = 30 + 60 C = 90 |
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#3
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Satyr,¡contigo hemos perdido a un buen profesor!
(what a good teacher we have lost!)
__________________
History, contrary to popular theories, "is" kings and dates and battles. Small Gods Terry Pratchett |
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